The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is :
Option
A. 2
B. 4
C. 6
D. 10
Correct answer is: B
EXPLANATION
Given, the maximum kinetic energy:
Kmax = 4eV
If V0 be the stopping potential, then K max = eVo
⇒ eVo = 4eV
⇒Vo =4V
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